A certain mass of saturated water vapour is contained in a cylindrical vessel under a weightless piston at one atmospheric pressure. The piston is slowly lowered till 0.7 g of vapour gets condensed. The volume under the piston is now only (1/5) th of the original volume. (Neglect the volume of liquid formed). Then -
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(a, c)
P 1 V 1 = n 1 RT
P 1 = vapour pressure = P 0
If piston is lowered slowly, then the process is isothermal
n 2 = n 1 /5
0.7gm vapour is condensed so
n – n 2 = 
…(i)
n 1 = 
…(ii)
Dividing (i) by (ii),
4m = 3.5
m = 
= 0.87
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